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0.0000857x^2+-0.00159x-0.5=0
We add all the numbers together, and all the variables
0.0000857x^2-0.00159x=0
a = 0.0000857; b = -0.00159; c = 0;
Δ = b2-4ac
Δ = -0.001592-4·0.0000857·0
Δ = 2.5281E-6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.00159)-\sqrt{2.5281E-6}}{2*0.0000857}=\frac{0.00159-\sqrt{2.5281E-6}}{0.0001714} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.00159)+\sqrt{2.5281E-6}}{2*0.0000857}=\frac{0.00159+\sqrt{2.5281E-6}}{0.0001714} $
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